周长 ((x+6)^2+(y-7)^2)/(17)=1

解答

周长

\frac{( x + 6 ) ^{2} + ( y - 7 ) ^{2}}{17} = 1

C = 217 π

求解步骤

C = 2 π r

求出半径

给定

\frac{( x + 6 ) ^{2} + ( y - 7 ) ^{2}}{17} = 1

的圆半径:

r = 17

C = 217 π

c i rc u m f ere n ce x^{2} + y^{2} \leq 9

c i rc u m f ere n ce (x - 6)^{2} + (y - 4)^{2} = 5^{2}

c i rc u m f ere n ce (x - 1)^{2} + y^{2} = 4

c i rc u m f ere n ce x^{2} + (y - 3)^{2} = 20

c i rc u m f ere n ce x^{2} - 3 x + 4 y + y^{2} = 16