3=(x+4)^2-y

Lösung

3 = (x + 4)^{2} - y

(h, k) = (- 4, - 3), p = \frac{1}{4}

Schritte zur Lösung

3 = (x + 4)^{2} - y

Rewrite

3 = (x + 4)^{2} - y

in the standard form:

4 \cdot \frac{1}{4} (y - (- 3)) = (x - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 4, - 3), p = \frac{1}{4}

(x - 5)^{2} = 4 (y - 3)

y^{2} - 12 x + 8 y + 88 = 0

2 x + y^{2} - y \leq 1

x^{2} + 3 y = 4

2 x^{2} + y = 3