半径 (x+1/2)^2+(y-4/5)^2= 9/4

解答

半径

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

r = \frac{3}{2}

求解步骤

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

将

(x + \frac{1}{2})^{2} + (y - \frac{4}{5})^{2} = \frac{9}{4}

改写为圆标准方程

(x - (- \frac{1}{2}))^{2} + (y - \frac{4}{5})^{2} = (\frac{3}{2})^{2}

因此圆的性质是:

(a, b) = (- \frac{1}{2}, \frac{4}{5}), r = \frac{3}{2}

半径是:

r = \frac{3}{2}

r a d i u s (x + \frac{8}{3})^{2} + y^{2} = 1

r a d i u s x^{2} + y^{2} - 10 x + 10 y + 49 = 0

r a d i u s x^{2} + y^{2} + 10 x - 6 y + 18 = 0

r a d i u s x^{2} + (y - 5)^{2} = 25

r a d i u s 3.5 (x + 2.2)^{2} + 3.5 (y - 11.1)^{2} - 21 = 0