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Beliebt Geometry >

leitkurve x=4y^2

Lösung

leitkurve

x = 4 y^{2}

Lösung

x = - \frac{1}{16}

Schritte zur Lösung

Rewrite

x = 4 y^{2}

in the standard form:

4 \cdot \frac{1}{16} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{16}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - \frac{1}{16}

Fasse zusammen

x = - \frac{1}{16}

Graph

Beliebte Beispiele

center 9x^2+4y^2=36

ce n t er 9 x^{2} + 4 y^{2} = 36

scheitelpunkte f(x)=x^2-x-6

v er t i ces f (x) = x^{2} - x - 6

3.5(x+2.2)^2+3.5(y-11.1)^2-21=0

3.5 (x + 2.2)^{2} + 3.5 (y - 11.1)^{2} - 21 = 0

y^{2} - 4 y + 4 x = - 16

((x-4)^2}{36}-\frac{(y-2)^2)/9 =1

\frac{( x - 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{9} = 1