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Beliebt Geometry >

center x^2+y^2+14x-2y+25=0

Lösung

center

x^{2} + y^{2} + 14 x - 2 y + 25 = 0

Lösung

(- 7, 1)

Schritte zur Lösung

x^{2} + y^{2} + 14 x - 2 y + 25 = 0

Rewrite

x^{2} + y^{2} + 14 x - 2 y + 25 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 1)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 7, 1), r = 5

And the center is:

(- 7, 1)

Graph

Beliebte Beispiele

center (x-1)^2+(y-4)^2=25

ce n t er (x - 1)^{2} + (y - 4)^{2} = 25

center 2(x-2)^2+2y^2=2

ce n t er 2 (x - 2)^{2} + 2 y^{2} = 2

center (x-4)^2+(y-5)^2=36

ce n t er (x - 4)^{2} + (y - 5)^{2} = 36

center x^2-8x+y^2-2y+8=0

ce n t er x^{2} - 8 x + y^{2} - 2 y + 8 = 0

center x^2+y^2-2x+3y-1=0

ce n t er x^{2} + y^{2} - 2 x + 3 y - 1 = 0