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Beliebt Geometry >

center x^2+y^2+8x-14y+1=0

Lösung

center

x^{2} + y^{2} + 8 x - 14 y + 1 = 0

Lösung

(- 4, 7)

Schritte zur Lösung

x^{2} + y^{2} + 8 x - 14 y + 1 = 0

Rewrite

x^{2} + y^{2} + 8 x - 14 y + 1 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 7)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 4, 7), r = 8

And the center is:

(- 4, 7)

Graph

Beliebte Beispiele

center x^2-14x+y^2+8y+40=0

ce n t er x^{2} - 14 x + y^{2} + 8 y + 40 = 0

center x^2+y^2-8x+2y=0

ce n t er x^{2} + y^{2} - 8 x + 2 y = 0

center x^2+(y+2)^2=4

ce n t er x^{2} + (y + 2)^{2} = 4

center (x-5)^2+(y+2)^2=16

ce n t er (x - 5)^{2} + (y + 2)^{2} = 16

center 2x^2+2y^2+16x+20y+18=0

ce n t er 2 x^{2} + 2 y^{2} + 16 x + 20 y + 18 = 0