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Beliebt Geometry >

center 4x^2+4y^2-16x+40y+67=0

Lösung

center

4 x^{2} + 4 y^{2} - 16 x + 40 y + 67 = 0

Lösung

(2, - 5)

Schritte zur Lösung

4 x^{2} + 4 y^{2} - 16 x + 40 y + 67 = 0

Rewrite

4 x^{2} + 4 y^{2} - 16 x + 40 y + 67 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 5))^{2} = (\frac{7}{2})^{2}

Therefore the circle properties are:

(a, b) = (2, - 5), r = \frac{7}{2}

And the center is:

(2, - 5)

Graph

Beliebte Beispiele

center (x-7/4)^2+(y+3/4)^2= 169/16

ce n t er (x - \frac{7}{4})^{2} + (y + \frac{3}{4})^{2} = \frac{169}{16}

center 4x^2+4y^2-16x-24y+51=0

ce n t er 4 x^{2} + 4 y^{2} - 16 x - 24 y + 51 = 0

center 2x^2+2y^2+10x-6y-55=0

ce n t er 2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

center x^2+y^2-12x-10y=-12

ce n t er x^{2} + y^{2} - 12 x - 10 y = - 12

center x^2+y^2-4x=5

ce n t er x^{2} + y^{2} - 4 x = 5