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Beliebt Geometry >

y^2+x^2+24x+10y+160=0

Lösung

y^{2} + x^{2} + 24 x + 10 y + 160 = 0

Lösung

(a, b) = (- 12, - 5), r = 3

Schritte zur Lösung

y^{2} + x^{2} + 24 x + 10 y + 160 = 0

Rewrite

y^{2} + x^{2} + 24 x + 10 y + 160 = 0

in the form of the standard circle equation

(x - (- 12))^{2} + (y - (- 5))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 12, - 5), r = 3

Graph

Beliebte Beispiele

(x+4)^2+(y-2)^2=((8^2))/((sqrt(5)))

(x + 4)^{2} + (y - 2)^{2} = \frac{( 8 ^{2} )}{( 5 )}

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(x - 1)^{2} + (y - 1)^{2} = 20

(x+1)^2+(y-2)^2=2

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x^{2} + y^{2} - 6 x - 4 y - 18 = 0

x^2+y^2-10x+20y+61=0

x^{2} + y^{2} - 10 x + 20 y + 61 = 0