x^2+y^2+6x+16y-8=0

解答

x^{2} + y^{2} + 6 x + 16 y - 8 = 0

(a, b) = (- 3, - 8), r = 9

求解步骤

x^{2} + y^{2} + 6 x + 16 y - 8 = 0

将

x^{2} + y^{2} + 6 x + 16 y - 8 = 0

改写为圆标准方程

(x - (- 3))^{2} + (y - (- 8))^{2} = 9^{2}

因此圆的性质是:

(a, b) = (- 3, - 8), r = 9

(x - \frac{1}{2 ( \frac{3}{2} )})^{2} + y^{2} = (\frac{1}{2 ( \frac{3}{2} )})^{2}

4 x^{2} - 24 x + 4 y^{2} + 20 y = 39

x^{2} + y^{2} + 14 x - 12 y = - 81

x^{2} - 16 x + 64 + y^{2} - 14 x + 49 = 0

x^{2} - 2 x + y^{2} = 15