2x^2-32x-y+127=0

Lösung

2 x^{2} - 32 x - y + 127 = 0

(h, k) = (8, - 1), p = \frac{1}{8}

Schritte zur Lösung

2 x^{2} - 32 x - y + 127 = 0

Rewrite

2 x^{2} - 32 x - y + 127 = 0

in the standard form

4 \cdot \frac{1}{8} (y - (- 1)) = (x - 8)^{2}

Therefore parabola properties are:

(h, k) = (8, - 1), p = \frac{1}{8}

- x + y^{2} = 5

x^{2} = - 19 y

x^{2} + y - 2 x - 3 = 0

y^{2} + 16 x = 0

y^{2} + 8 x - 6 y + 25 = 0