3y^2+6x-y+2=0

Lösung

3 y^{2} + 6 x - y + 2 = 0

(h, k) = (- \frac{23}{72}, \frac{1}{6}), p = - \frac{1}{2}

Schritte zur Lösung

3 y^{2} + 6 x - y + 2 = 0

Rewrite

3 y^{2} + 6 x - y + 2 = 0

in the standard form

4 (- \frac{1}{2}) (x - (- \frac{23}{72})) = (y - \frac{1}{6})^{2}

Therefore parabola properties are:

(h, k) = (- \frac{23}{72}, \frac{1}{6}), p = - \frac{1}{2}

(x - 1)^{2} = 12 y

y^{2} + x = 3

y^{2} = 6 x - 32

20 x = y^{2}

4 x^{2} - 8 x + 2 y = 5