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Beliebt Geometry >

4x^2-12x+4y^2+16y-5=0

Lösung

4 x^{2} - 12 x + 4 y^{2} + 16 y - 5 = 0

Lösung

(a, b) = (\frac{3}{2}, - 2), r = \frac{15}{2}

Schritte zur Lösung

4 x^{2} - 12 x + 4 y^{2} + 16 y - 5 = 0

Rewrite

4 x^{2} - 12 x + 4 y^{2} + 16 y - 5 = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- 2))^{2} = (\frac{15}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - 2), r = \frac{15}{2}

Graph

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