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Beliebt Geometry >

4x^2+4y^2+24x-16y-51=0

Lösung

4 x^{2} + 4 y^{2} + 24 x - 16 y - 51 = 0

Lösung

(a, b) = (- 3, 2), r = \frac{103}{2}

Schritte zur Lösung

4 x^{2} + 4 y^{2} + 24 x - 16 y - 51 = 0

Rewrite

4 x^{2} + 4 y^{2} + 24 x - 16 y - 51 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 2)^{2} = (\frac{103}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 3, 2), r = \frac{103}{2}

Graph

Beliebte Beispiele

x^2+(y-10)^2=10

x^{2} + (y - 10)^{2} = 10

x^2+y^2-6x-6y+9=0

x^{2} + y^{2} - 6 x - 6 y + 9 = 0

x^2+y^2-4x+10y+25=0

x^{2} + y^{2} - 4 x + 10 y + 25 = 0

(x+3)^2+(y+5/4)^2=(11/2)^2

(x + 3)^{2} + (y + \frac{5}{4})^{2} = (\frac{11}{2})^{2}

(x+3)^2+(y+5)^2=9

(x + 3)^{2} + (y + 5)^{2} = 9