(x-1/2)^2+(y+1/4)^2=8

解

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = 8

(a, b) = (\frac{1}{2}, - \frac{1}{4}), r = 8

解答ステップ

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = 8

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = 8

を標準的な円のequationの形式で書き換える

(x - \frac{1}{2})^{2} + (y - (- \frac{1}{4}))^{2} = (8)^{2}

ゆえに円の特性は:

(a, b) = (\frac{1}{2}, - \frac{1}{4}), r = 8