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Beliebt Geometry >

2x^2+2y^2+3x+5y-5=0

Lösung

2 x^{2} + 2 y^{2} + 3 x + 5 y - 5 = 0

Lösung

(a, b) = (- \frac{3}{4}, - \frac{5}{4}), r = \frac{37}{2 2}

Schritte zur Lösung

2 x^{2} + 2 y^{2} + 3 x + 5 y - 5 = 0

Rewrite

2 x^{2} + 2 y^{2} + 3 x + 5 y - 5 = 0

in the form of the standard circle equation

(x - (- \frac{3}{4}))^{2} + (y - (- \frac{5}{4}))^{2} = (\frac{37}{2 2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{3}{4}, - \frac{5}{4}), r = \frac{37}{2 2}

Graph

Beliebte Beispiele

(x-1)^2+(y+1)^2=2

(x - 1)^{2} + (y + 1)^{2} = 2

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x^{2} + y^{2} - 6 x - 8 y - 17 = 0

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y^2+x^2-2x+10y=-25

y^{2} + x^{2} - 2 x + 10 y = - 25