x^2+y^2-2x-2y-7=0

解答

x^{2} + y^{2} - 2 x - 2 y - 7 = 0

(a, b) = (1, 1), r = 3

求解步骤

x^{2} + y^{2} - 2 x - 2 y - 7 = 0

将

x^{2} + y^{2} - 2 x - 2 y - 7 = 0

改写为圆标准方程

(x - 1)^{2} + (y - 1)^{2} = 3^{2}

因此圆的性质是:

(a, b) = (1, 1), r = 3

4 x^{2} + 4 y^{2} - 20 x - 32 y + 81 = 0

x^{2} + y^{2} + 6 x + 4 y - 3 = 0

(x - 2)^{2} + (y - 2)^{2} = 2

3 x^{2} + 3 y^{2} - 10 = 0

x^{2} + y^{2} - 3 x + 5 y - 14 = 0