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Beliebt Geometry >

x^2-4x+y^2+6y+12=0

Lösung

x^{2} - 4 x + y^{2} + 6 y + 12 = 0

Lösung

(a, b) = (2, - 3), r = 1

Schritte zur Lösung

x^{2} - 4 x + y^{2} + 6 y + 12 = 0

Rewrite

x^{2} - 4 x + y^{2} + 6 y + 12 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = 1

Graph

Beliebte Beispiele

50=30-13x+5y+(x^2)/2+(y^2)/2

50 = 30 - 13 x + 5 y + \frac{x ^{2}}{2} + \frac{y ^{2}}{2}

x^2+y^2=10-x^2-y^2

x^{2} + y^{2} = 10 - x^{2} - y^{2}

x^2+y^2-12y=-32

x^{2} + y^{2} - 12 y = - 32

x^2+(y-1)^2<= 25

x^{2} + (y - 1)^{2} \leq 25

(x+2)^2+(y+1)^2=4

(x + 2)^{2} + (y + 1)^{2} = 4