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Beliebt Geometry >

4x^2+4y^2+20x-32y=5

Lösung

4 x^{2} + 4 y^{2} + 20 x - 32 y = 5

Lösung

(a, b) = (- \frac{5}{2}, 4), r = \frac{47}{2}

Schritte zur Lösung

4 x^{2} + 4 y^{2} + 20 x - 32 y = 5

Rewrite

4 x^{2} + 4 y^{2} + 20 x - 32 y = 5

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - 4)^{2} = (\frac{47}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, 4), r = \frac{47}{2}

Graph

Beliebte Beispiele

x^2+y^2-20x+16y+128=0

x^{2} + y^{2} - 20 x + 16 y + 128 = 0

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\frac{( x - 3 ) ^{2} + y ^{2}}{4} = 1

(x+4)^2+(y+2)^2=25

(x + 4)^{2} + (y + 2)^{2} = 25