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Beliebt Geometry >

x^2+y^2+32x+14y+296=0

Lösung

x^{2} + y^{2} + 32 x + 14 y + 296 = 0

Lösung

(a, b) = (- 16, - 7), r = 3

Schritte zur Lösung

x^{2} + y^{2} + 32 x + 14 y + 296 = 0

Rewrite

x^{2} + y^{2} + 32 x + 14 y + 296 = 0

in the form of the standard circle equation

(x - (- 16))^{2} + (y - (- 7))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 16, - 7), r = 3

Graph

Beliebte Beispiele

(x-2)^2+(y-3)^2=16

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x^{2} + y^{2} + 10 x - 6 y + 33 = 0

3(x-4)^2+3y^2=54

3 (x - 4)^{2} + 3 y^{2} = 54

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