en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(n)=((4^n-1))/((2^n-1))

Solution

f (n) = \frac{( 4 ^{n} - 1 )}{( 2 ^{n} - 1 )}

Solution

Domain : n < 0 or n > 0

Range : - \infty < f (x) < \infty

Intercepts : None

Asymptotes : Horizontal y = 1

Extreme Points : None

+1

Solution steps

Domain of

\frac{4 ^{n} - 1}{2 ^{n} - 1} : n < 0 or n > 0

Range of

\frac{4 ^{n} - 1}{2 ^{n} - 1} : - \infty < f (x) < \infty

Axis interception points of

\frac{4 ^{n} - 1}{2 ^{n} - 1} :

None

Asymptotes of

\frac{4 ^{n} - 1}{2 ^{n} - 1} :

Horizontal

: y = 1

Extreme Points of

\frac{4 ^{n} - 1}{2 ^{n} - 1} :

None

Popular Examples

f(x)=cos(x^3)sin^2(x^5)

f (x) = cos (x^{3}) sin^{2} (x^{5})

f (m) = m^{4} - m^{2} + 1

y = 2 e^{5} x + 3

f (n) = 5 n - 4

f(x)=12x^2-7x+3

f (x) = 12 x^{2} - 7 x + 3

Frequently Asked Questions (FAQ)

What is the f(n)=((4^n-1))/((2^n-1)) ?
The f(n)=((4^n-1))/((2^n-1)) is