What is the f(x)=-0.1x^3-0.3x^2+0.4x+3.2 ?

The f(x)=-0.1x^3-0.3x^2+0.4x+3.2 is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(x)=-0.1x^3-0.3x^2+0.4x+3.2

f (x) = - 0.1 x^{3} - 0.3 x^{2} + 0.4 x + 3.2

Domain : - \infty < x < \infty

Range : - \infty < f (x) < \infty

X Intercepts : (2.73617 \dots, 0), Y Intercepts : (0, 3.2)

Asymptotes : None

Extreme Points : Minimum (- \frac{3 + 21}{3}, 1.88715 \dots), Maximum (\frac{21 - 3}{3}, 3.31284 \dots)

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

- 0.1 x^{3} - 0.3 x^{2} + 0.4 x + 3.2 : - \infty < x < \infty

Range of

- 0.1 x^{3} - 0.3 x^{2} + 0.4 x + 3.2 : - \infty < f (x) < \infty

Axis interception points of

- 0.1 x^{3} - 0.3 x^{2} + 0.4 x + 3.2 :

X Intercepts

: (2.73617 \dots, 0),

Y Intercepts

: (0, 3.2)

Asymptotes of

- 0.1 x^{3} - 0.3 x^{2} + 0.4 x + 3.2 :

None

Extreme Points of

- 0.1 x^{3} - 0.3 x^{2} + 0.4 x + 3.2 :

Minimum

(- \frac{3 + 21}{3}, 1.88715 \dots),

Maximum

(\frac{21 - 3}{3}, 3.31284 \dots)

f (x) = 3 \cdot x^{2} + 10 x + 83

f (m) = m^{2} - 2 m + 4

y = (x - 1)^{2} + 6

f (x) = 6 x^{2} - 5 x + 1

y = (\frac{1 + 4}{x})^{x}