What is the asymptotes of h(x)=(x^2+2x)/(x+1) ?

The asymptotes of h(x)=(x^2+2x)/(x+1) is Vertical: x=-1,Slant: y=x+1

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asymptotes of h(x)=(x^2+2x)/(x+1)

asymptotes

h (x) = \frac{x ^{2} + 2 x}{x + 1}

Vertical : x = - 1, Slant : y = x + 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 2 x}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 2 x}{x + 1} : y = x + 1

Vertical : x = - 1, Slant : y = x + 1

f (x) = \frac{( x - 2 )}{( x + 2 )}

6 x + 36 x^{2} - 25 x + 101

\frac{- 2}{x ^{2}}

f (x) = \frac{9 x ^{2}}{x - 7}

f (x) = \frac{9 x ^{2}}{x - 2}

What is the asymptotes of h(x)=(x^2+2x)/(x+1) ?
The asymptotes of h(x)=(x^2+2x)/(x+1) is Vertical: x=-1,Slant: y=x+1