What is the asymptotes of f(x)=log_{2}(x+1) ?

The asymptotes of f(x)=log_{2}(x+1) is Vertical: x=-1

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asymptotes of f(x)=log_{2}(x+1)

asymptotes

f (x) = lo g_{2} (x + 1)

Vertical : x = - 1

Solution steps

Vertical asymptotes of

lo g_{2} (x + 1) : x = - 1

Horizontal Asymptotes of

lo g_{2} (x + 1) :

None

Slant Asymptotes of

lo g_{2} (x + 1) :

None

Vertical : x = - 1

f (x) = x + \frac{4}{x ^{2}}

y = + (- 2) x

f (x) = \frac{( x - 4 )}{2 x + 5}

f (x) = \frac{x - 6}{x} - 1

f (x) = \frac{x ^{2} + 6}{x}

What is the asymptotes of f(x)=log_{2}(x+1) ?
The asymptotes of f(x)=log_{2}(x+1) is Vertical: x=-1