critical cos(5x),0<= x<= 2pi

Lösung

kritische punkte

cos (5 x), 0 \leq x \leq 2 π

x = 0, x = \frac{π}{5}, x = \frac{2 π}{5}, x = \frac{3 π}{5}, x = \frac{4 π}{5}, x = π, x = \frac{6 π}{5}, x = \frac{7 π}{5}, x = \frac{8 π}{5}, x = \frac{9 π}{5}, x = 2 π

Schritte zur Lösung

cos (5 x), 0 \leq x \leq 2 π

Suche

f^{'} (x)

, an dem die Funktion gleich Null oder unbestimmt ist

x = \frac{π}{5}, x = \frac{2 π}{5}, x = \frac{3 π}{5}, x = \frac{4 π}{5}, x = π, x = \frac{6 π}{5}, x = \frac{7 π}{5}, x = \frac{8 π}{5}, x = \frac{9 π}{5}

Bestimme kritische Punkte, die nicht innerhalb des

f (x)

Bereiches liegen

Bereich von

cos (5 x), 0 \leq x \leq 2 π : 0 \leq x \leq 2 π

Alle kritischen Punkte liegen in der Domäne

x = \frac{π}{5}, x = \frac{2 π}{5}, x = \frac{3 π}{5}, x = \frac{4 π}{5}, x = π, x = \frac{6 π}{5}, x = \frac{7 π}{5}, x = \frac{8 π}{5}, x = \frac{9 π}{5}

Evaluaiere Intervallendpunkt

x = 0 :

kritischer Punkt

Evaluaiere Intervallendpunkt

x = 2 π :

kritischer Punkt

x = 0, x = \frac{π}{5}, x = \frac{2 π}{5}, x = \frac{3 π}{5}, x = \frac{4 π}{5}, x = π, x = \frac{6 π}{5}, x = \frac{7 π}{5}, x = \frac{8 π}{5}, x = \frac{9 π}{5}, x = 2 π

cr i t i c a l 2 x e^{x^{2}}

e x t re m e f (x, y) = (3 x + 4 x^{3}) (y^{2} + 2 y)

cr i t i c a l y = x^{3}

cr i t i c a l f (x) = x - 6 x

cr i t i c a l f (x) = (x - 2) (x + 1)