What is the critical f(x)=x^2+(250)/x ?

The critical f(x)=x^2+(250)/x is x=5

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critical f(x)=x^2+(250)/x

critical points

f (x) = x^{2} + \frac{250}{x}

x = 5

Solution steps

x^{2} + \frac{250}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = 5, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} + \frac{250}{x} : x < 0 or x > 0

x^{2} + \frac{250}{x}

is not defined at

x = 0

, therefore:

x = 5

f (x, y) = 2 x^{2} - 4 y^{3}

h (x) = \frac{e ^{4 x}}{x + 1}

f (x) = \frac{x}{x ^{2} + 64}

\frac{4 x}{x ^{2} + 1} - 1

f (x) = x^{2} - 4 x y + 2 y^{2} + 4 x + 8 y + 4