What is the critical f(x)=(x^2+x)*(x^2-1)^{-1} ?

The critical f(x)=(x^2+x)*(x^2-1)^{-1} is None

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critical f(x)=(x^2+x)*(x^2-1)^{-1}

critical points

f (x) = (x^{2} + x) \cdot (x^{2} - 1)^{- 1}

None

Solution steps

(x^{2} + x) (x^{2} - 1)^{- 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = 1

Identify critical points not in

f (x)

domain

Domain of

(x^{2} + x) \cdot (x^{2} - 1)^{- 1} : x < - 1 or - 1 < x < 1 or x > 1

(x^{2} + x) \cdot (x^{2} - 1)^{- 1}

is not defined at

x = 1

, therefore:

None

x^{4} + 2 x^{3} - 2 x^{2} + 4

f (x) = \frac{x ^{2} + x}{x ^{2} - 1}

2 x - 3 y + 6

\frac{x}{x ^{2} + 2}

x^{4} (x - 3)^{3}

What is the critical f(x)=(x^2+x)*(x^2-1)^{-1} ?
The critical f(x)=(x^2+x)*(x^2-1)^{-1} is None