What is the critical f(x)=0.05e^{2x}(x^2-10x+19) ?

The critical f(x)=0.05e^{2x}(x^2-10x+19) is x=2,x=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=0.05e^{2x}(x^2-10x+19)

critical points

f (x) = 0.05 e^{2 x} (x^{2} - 10 x + 19)

x = 2, x = 7

Solution steps

0.05 e^{2 x} (x^{2} - 10 x + 19)

Find where

f^{'} (x)

is equal to zero or undefined

x = 2, x = 7

Identify critical points not in

f (x)

domain

Domain of

0.05 e^{2 x} (x^{2} - 10 x + 19) : - \infty < x < \infty

All critical points are in domain

x = 2, x = 7

f (x) = 3 x^{2} + 6 x - 9

f (x) = x y + \frac{1}{x} + \frac{1}{y}

ln (9 - x^{2})

g (x) = \frac{1}{1 + x ^{2}}

f (x) = x^{4} - 4 x^{3} + 16 x

What is the critical f(x)=0.05e^{2x}(x^2-10x+19) ?
The critical f(x)=0.05e^{2x}(x^2-10x+19) is x=2,x=7