What is the critical f(x)= 1/(sqrt(1-x^2)) ?

The critical f(x)= 1/(sqrt(1-x^2)) is x=0

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critical f(x)= 1/(sqrt(1-x^2))

critical

x = 0

Solution steps

\frac{1}{1 - x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{1 - x ^{2}} : - 1 < x < 1

\frac{1}{1 - x ^{2}}

is not defined at

x = - 1, x = 1

, therefore:

x = 0

What is the critical f(x)= 1/(sqrt(1-x^2)) ?
The critical f(x)= 1/(sqrt(1-x^2)) is x=0