What is the extreme f(x)=6x^5-40x^3+45 ?

The extreme f(x)=6x^5-40x^3+45 is Maximum(-2,173),Saddle(0,45),Minimum(2,-83)

Popular >

extreme f(x)=6x^5-40x^3+45

extreme points

f (x) = 6 x^{5} - 40 x^{3} + 45

Maximum (- 2, 173), Saddle (0, 45), Minimum (2, - 83)

Solution steps

f^{'} (x) = 30 x^{4} - 120 x^{2}

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

6 x^{5} - 40 x^{3} + 45 : 173

Maximum (- 2, 173)

Plug

x = 0

into

6 x^{5} - 40 x^{3} + 45 : 45

Saddle (0, 45)

Plug

x = 2

into

6 x^{5} - 40 x^{3} + 45 : - 83

Minimum (2, - 83)

Maximum (- 2, 173), Saddle (0, 45), Minimum (2, - 83)

f (t) = t^{2} u (t) - (3 t - 2) u (t - 2)

f (x) = x^{\frac{4}{5}} (x + 1)

f (x) = x^{3} - 3 x, - 2 \leq x \leq 2

f (x, y) = - x^{2} - 3 y^{2} - 2 x y + 4 x - 3

f (x, y) = 13 x e^{y}

What is the extreme f(x)=6x^5-40x^3+45 ?
The extreme f(x)=6x^5-40x^3+45 is Maximum(-2,173),Saddle(0,45),Minimum(2,-83)