extreme f(x)=3\sqrt[3]{x}-4x

Lösung

extrempunkte

f (x) = 3 3 x - 4 x

Minimum (- \frac{1}{8}, - 1), Minimum (\frac{1}{8}, 1)

Schritte zur Lösung

f^{'} (x) = \frac{1}{x ^{\frac{2}{3}}} - 4

Intervalle finden:

Ansteigend

: - \infty < x < - 8,

Absteigend

: - 8 < x < 8,

Ansteigend

: 8 < x < \infty

Stecke

x = - \frac{1}{8}

3 3 x - 4 x : - 1

Minimum (- \frac{1}{8}, - 1)

Stecke

x = \frac{1}{8}

3 3 x - 4 x : 1

Minimum (\frac{1}{8}, 1)

Minimum (- \frac{1}{8}, - 1), Minimum (\frac{1}{8}, 1)

e x t re m e y = \frac{( ln ( x ) ) ^{2}}{x}

e x t re m e f (x, y) = - x^{3} + 2 y^{3} + 27 x - 24 y + 3

e x t re m e f (x) = \frac{x ^{2}}{e ^{x}}

e x t re m e F (I, J) = (- 3 I + 2 J)

e x t re m e 0.5 x^{2} - 130 x + 17555