extreme y=x^2-4x-5

解答

极值点

y = x^{2} - 4 x - 5

极小值 (2, - 9)

求解步骤

f^{'} (x) = 2 x - 4

Find intervals:

递减

: - \infty < x < 2,

递增

: 2 < x < \infty

将

x = 2

代入

x^{2} - 4 x - 5 : - 9

极小值 (2, - 9)

e x t re m e x^{3} - 6 x^{2} + 9 x + 9

e x t re m e f (x, y) = 16 - x^{2} - y^{2}

e x t re m e f (x, y) = 2 x^{3} + 3 y^{2} - 4 x y - 4

e x t re m e - 1.8 x^{2} + 7 x - 11

e x t re m e f (x, y) = 2 ln (x) + ln (y) - 4 x - y