extreme (x-2)^2+1

Lösung

extrempunkte

(x - 2)^{2} + 1

Minimum (2, 1)

Schritte zur Lösung

f^{'} (x) = 2 x - 4

Intervalle finden:

Absteigend

: - \infty < x < 2,

Ansteigend

: 2 < x < \infty

Stecke

x = 2

(x - 2)^{2} + 1 : 1

Minimum (2, 1)

e x t re m e f (x) = sin (x), 0 \leq x < \frac{π}{2}

e x t re m e f (x) = (x^{2} - 4)^{2} - 4

e x t re m e f (x) = \frac{2}{3} x^{3} - 4 x^{2} - 45 x

e x t re m e f (x, y) = x^{2} + x y + y^{2} - 37 y + 456

e x t re m e f (x, y) = 3 x^{2} - y^{2}