What is the extreme f(x)=x^4-50x^2+8 ?

The extreme f(x)=x^4-50x^2+8 is Minimum(-5,-617),Maximum(0,8),Minimum(5,-617)

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extreme f(x)=x^4-50x^2+8

extreme points

f (x) = x^{4} - 50 x^{2} + 8

Minimum (- 5, - 617), Maximum (0, 8), Minimum (5, - 617)

Solution steps

f^{'} (x) = 4 x^{3} - 100 x

Find intervals:

Decreasing

: - \infty < x < - 5,

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

x^{4} - 50 x^{2} + 8 : - 617

Minimum (- 5, - 617)

Plug

x = 0

into

x^{4} - 50 x^{2} + 8 : 8

Maximum (0, 8)

Plug

x = 5

into

x^{4} - 50 x^{2} + 8 : - 617

Minimum (5, - 617)

Minimum (- 5, - 617), Maximum (0, 8), Minimum (5, - 617)

f (x) = x^{3} + 2 x y + y^{2} - 5 x

f (x) = 24 x^{3} - 3 x^{4} = x^{3} (24 - 3 x)

f (x) = ∣ sin (x) ∣, (- π, π)

f (x) = \frac{x ^{2} - 63}{x - 8}

2 y^{2} + 2 x y + x^{2} + 2 y - 2 x + 1

What is the extreme f(x)=x^4-50x^2+8 ?
The extreme f(x)=x^4-50x^2+8 is Minimum(-5,-617),Maximum(0,8),Minimum(5,-617)