What is the extreme f(x)=x^2(2-x^2) ?

The extreme f(x)=x^2(2-x^2) is Maximum(-1,1),Minimum(0,0),Maximum(1,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^2(2-x^2)

extreme points

f (x) = x^{2} (2 - x^{2})

Maximum (- 1, 1), Minimum (0, 0), Maximum (1, 1)

Solution steps

f^{'} (x) = - 4 x (x + 1) (x - 1)

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 0,

Increasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

x^{2} (2 - x^{2}) : 1

Maximum (- 1, 1)

Plug

x = 0

into

x^{2} (2 - x^{2}) : 0

Minimum (0, 0)

Plug

x = 1

into

x^{2} (2 - x^{2}) : 1

Maximum (1, 1)

Maximum (- 1, 1), Minimum (0, 0), Maximum (1, 1)

f (x, y) = x^{2} + 2 x y + 3 y^{2}

f (x) = \frac{x ^{2}}{x + 3}

x

5

K (r, s) = 8 r - s

What is the extreme f(x)=x^2(2-x^2) ?
The extreme f(x)=x^2(2-x^2) is Maximum(-1,1),Minimum(0,0),Maximum(1,1)