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Popular >

extreme f(x)=(x-4)/(x^2)

Solution

extreme points

f (x) = \frac{x - 4}{x ^{2}}

Solution

Maximum (8, \frac{1}{16})

Solution steps

f^{'} (x) = \frac{- x + 8}{x ^{3}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 8,

Decreasing

: 8 < x < \infty

Plug

x = 8

into

\frac{x - 4}{x ^{2}} : \frac{1}{16}

Maximum (8, \frac{1}{16})

Popular Examples

extreme f(x,y)=10+x^2+2y^2 extreme points

f (x, y) = 10 + x^{2} + 2 y^{2}

extreme f(x)=(4x^2)/(4x-8)extreme points

f (x) = \frac{4 x ^{2}}{4 x - 8}

extreme x^4-x^3-3x^2+5x-2 extreme points

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extreme 2x^3+9xy^2+15x^2+27y^2 extreme points

2 x^{3} + 9 x y^{2} + 15 x^{2} + 27 y^{2}

extreme f(x,y)=e^{x^2+y^2-4y}extreme points

f (x, y) = e^{x^{2} + y^{2} - 4 y}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x-4)/(x^2) ?
The extreme f(x)=(x-4)/(x^2) is Maximum(8, 1/16)