What is the extreme f(x)=x^3-3x^2-9x+10 ?

The extreme f(x)=x^3-3x^2-9x+10 is Maximum(-1,15),Minimum(3,-17)

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extreme f(x)=x^3-3x^2-9x+10

extreme points

f (x) = x^{3} - 3 x^{2} - 9 x + 10

Maximum (- 1, 15), Minimum (3, - 17)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x^{2} - 9 x + 10 : 15

Maximum (- 1, 15)

Plug

x = 3

into

x^{3} - 3 x^{2} - 9 x + 10 : - 17

Minimum (3, - 17)

Maximum (- 1, 15), Minimum (3, - 17)

f (x) = x 4 - x^{2}, - 1 \leq x \leq 2

f (x) = \frac{x ^{2}}{x ^{2} - 3}

f (x, y) = x y^{2} + x^{2} y

f (x) = \frac{1}{x + 2}

f (x, y) = x^{3} + y^{3} - 3 x^{2} - 6 y^{2} - 9 x

What is the extreme f(x)=x^3-3x^2-9x+10 ?
The extreme f(x)=x^3-3x^2-9x+10 is Maximum(-1,15),Minimum(3,-17)