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Frequently Asked Questions (FAQ)
What is the extreme f(x)=3x^2y+y^3-3x^2-3y^2+2 ?
- The extreme f(x)=3x^2y+y^3-3x^2-3y^2+2 is Minimum(0,2),Maximum(0,0),Saddle(1,1),Saddle(-1,1)