What is the extreme f(x)=x^4-8x^3+10 ?

The extreme f(x)=x^4-8x^3+10 is Saddle(0,10),Minimum(6,-422)

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extreme f(x)=x^4-8x^3+10

extreme points

f (x) = x^{4} - 8 x^{3} + 10

Saddle (0, 10), Minimum (6, - 422)

Solution steps

f^{'} (x) = 4 x^{3} - 24 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 0

into

x^{4} - 8 x^{3} + 10 : 10

Saddle (0, 10)

Plug

x = 6

into

x^{4} - 8 x^{3} + 10 : - 422

Minimum (6, - 422)

Saddle (0, 10), Minimum (6, - 422)

f (x) = x^{3} - 6 x^{2} + 9 x - 3

f (x) = x^{3} - 6 x^{2} + 9 x + 3

x - 2 + 4 - x

f (x, y) = y e^{x} - 2 e^{x} - e^{y} + 5

f (x, y) = e^{2 x y}

What is the extreme f(x)=x^4-8x^3+10 ?
The extreme f(x)=x^4-8x^3+10 is Saddle(0,10),Minimum(6,-422)