What is the domain of f(x)= 1/(sqrt(4x-x^2)) ?

The domain of f(x)= 1/(sqrt(4x-x^2)) is 0<x<4

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domain of f(x)= 1/(sqrt(4x-x^2))

domain

f (x) = \frac{1}{4 x - x ^{2}}

0 < x < 4

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 4

Find undefined (singularity) points:

x = 0, x = 4

Combine real regions and undefined points for final function domain

0 < x < 4

f (x) = \frac{8}{x - 2}

f (x) = \frac{11 x - 20}{13 x - 13}

7 + (ln (x^{2} - 16))^{2}

10 x + 15

y = \frac{5 ln ( x )}{x ^{3}}

What is the domain of f(x)= 1/(sqrt(4x-x^2)) ?
The domain of f(x)= 1/(sqrt(4x-x^2)) is 0<x<4