What is the domain of f(x)=sqrt((x^2-16)/x) ?

The domain of f(x)=sqrt((x^2-16)/x) is -4 = 4

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domain of f(x)=sqrt((x^2-16)/x)

domain

f (x) = \frac{x ^{2} - 16}{x}

- 4 \leq x < 0 or x \geq 4

Solution steps

Find non-negative values for radicals:

- 4 \leq x < 0 or x \geq 4

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 4 \leq x < 0 or x \geq 4

f (x) = (\frac{3}{2})^{x + 2} - 1

f (x) = \frac{4 x ^{2} + 2 x - 2}{4 x - 2}

f (x) = x - 2005

f (x) = \frac{x}{1 - x + 1}

\frac{x + 5}{( x + 8 ) ( x - 9 )}

What is the domain of f(x)=sqrt((x^2-16)/x) ?
The domain of f(x)=sqrt((x^2-16)/x) is -4<= x<0\lor x>= 4