定义域 g(x)=((x+3))/((x^2-64))

解答

定义域

g (x) = \frac{( x + 3 )}{( x ^{2} - 64 )}

x < - 8 or - 8 < x < 8 or x > 8

间隔符号

(- \infty, - 8) \cup (- 8, 8) \cup (8, \infty)

求解步骤

找到无定义的点（奇点）:

x = 8, x = - 8

函数定义域

x < - 8 or - 8 < x < 8 or x > 8

d o main \frac{x ^{2}}{2 x - 5}

d o main f (x) = \frac{1}{t ^{2} - 1}

d o main arcsin (\frac{x}{4})

d o main f (x) = \frac{1}{lo g _{x + 1} ( 2 )}

d o main \frac{x + 7}{2 x - 2}