定义域-(10-3x)/(1+8x)

解答

定义域

- \frac{10 - 3 x}{1 + 8 x}

x < - \frac{1}{8} or x > - \frac{1}{8}

间隔符号

(- \infty, - \frac{1}{8}) \cup (- \frac{1}{8}, \infty)

求解步骤

找到无定义的点（奇点）:

x = - \frac{1}{8}

函数定义域

x < - \frac{1}{8} or x > - \frac{1}{8}

d o main f (x) = (x)^{2}

d o main f (x) = \frac{- x ( 1 - x )}{3 x ^{2} + 5 x - 2}

d o main f (x) = x^{2} - 7 x + 12

d o main f (x) = 2 x^{3} - 3 x^{2} + 6, - 1 \leq x \leq 1

d o main y = ln (27 + 8 x^{3})