en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=x^2+sqrt(x)

Solution

domain

f (x) = x^{2} + x

Solution

x \geq 0

+1

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

Popular Examples

domain of f(x)=(2x^2-6x)/(x^2-2x-3)domain

f (x) = \frac{2 x ^{2} - 6 x}{x ^{2} - 2 x - 3}

domain of f(x)=2sqrt(x+2)domain

f (x) = 2 x + 2

domain of f(x)=(2x^2-6x+4)/(-3x+5)domain

f (x) = \frac{2 x ^{2} - 6 x + 4}{- 3 x + 5}

domain of x^2+10 domain

x^{2} + 10

domain of f(x)=(3x-2)/(x+2)domain

f (x) = \frac{3 x - 2}{x + 2}

Frequently Asked Questions (FAQ)

What is the domain of f(x)=x^2+sqrt(x) ?
The domain of f(x)=x^2+sqrt(x) is x>= 0