What is the domain of f(x)=x^2+4x-1,x>=-2-sqrt(5) ?

The domain of f(x)=x^2+4x-1,x>=-2-sqrt(5) is x>=-2-sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of f(x)=x^2+4x-1,x>=-2-sqrt(5)

domain

f (x) = x^{2} + 4 x - 1, x \geq - 2 - 5

x \geq - 2 - 5

Interval Notation

Solution steps

Set the domain to the given interval

x \geq - 2 - 5

The function has no undefined points nor domain constraints. Therefore, the domain is

x \geq - 2 - 5

f (x) = \frac{( x ^{2} - 4 )}{1 - x ^{2}}

f (x) = x^{3} - 12 x + 1

6 x^{2} - 18 x + 12

y = \frac{x + 2}{x ^{2} - 121}

\frac{1}{4 x ^{2} - 4 x - 3}

What is the domain of f(x)=x^2+4x-1,x>=-2-sqrt(5) ?
The domain of f(x)=x^2+4x-1,x>=-2-sqrt(5) is x>=-2-sqrt(5)