What is the domain of f(x)=sqrt((2x)/(x^2-9)) ?

The domain of f(x)=sqrt((2x)/(x^2-9)) is -3 3

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domain of f(x)=sqrt((2x)/(x^2-9))

domain

- 3 < x \leq 0 or x > 3

Interval Notation

Solution steps

Find non-negative values for radicals:

- 3 < x \leq 0 or x > 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 3 < x \leq 0 or x > 3

What is the domain of f(x)=sqrt((2x)/(x^2-9)) ?
The domain of f(x)=sqrt((2x)/(x^2-9)) is -3<x<= 0\lor x>3