We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the domain of f(x)=sqrt(16x^2-2) ?
- The domain of f(x)=sqrt(16x^2-2) is x<=-1/(2sqrt(2))\lor x>= 1/(2sqrt(2))