What is the domain of y= 1/(x^2-x) ?

The domain of y= 1/(x^2-x) is x 1

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domain of y= 1/(x^2-x)

domain

y = \frac{1}{x ^{2} - x}

x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = 0

The function domain

x < 0 or 0 < x < 1 or x > 1

\frac{x ^{2} - 4 x - 1}{7}

\frac{3 - 3 x}{x ^{2} - 2 x + 1}

\frac{7 x - 21}{x ^{2} - 81}

f (x) = y^{2} + 8 x + 6 y + 25 = 0

f (x) = \frac{x ^{2} + 4 x}{3 x ^{2} - 12}

What is the domain of y= 1/(x^2-x) ?
The domain of y= 1/(x^2-x) is x<0\lor 0<x<1\lor x>1