What is the domain of y= x/(x^2+1) ?

The domain of y= x/(x^2+1) is -infinity <x<infinity

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domain of y= x/(x^2+1)

domain

y = \frac{x}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{x ^{2} - x}{x ^{2} - 1}

f (x) = \frac{x}{x - 1 - 1}

f (x) = \frac{( 2 x ^{2} - x + 3 )}{( x ^{2} + 1 )}

∣ 4 x - 3 ∣

f (x) = lo g_{4} (x + 2)

What is the domain of y= x/(x^2+1) ?
The domain of y= x/(x^2+1) is -infinity <x<infinity