What is the domain of f(x)=ln(2+ln(x)) ?

The domain of f(x)=ln(2+ln(x)) is x> 1/(e^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=ln(2+ln(x))

domain

f (x) = ln (2 + ln (x))

x > \frac{1}{e ^{2}}

Interval Notation

(\frac{1}{e ^{2}}, \infty)

Solution steps

Find positive values for logs:

x > \frac{1}{e ^{2}}

The function domain

x > \frac{1}{e ^{2}}

f (x) = \frac{( x + 1 )}{x ^{2} - 1}

f (x) = \frac{3 x - 6}{x ^{2} - 6}

\frac{x + 2}{9 x + 4}

g (x) = 6 x - 2

f (x) = 2^{x + 3}

What is the domain of f(x)=ln(2+ln(x)) ?
The domain of f(x)=ln(2+ln(x)) is x> 1/(e^2)