What is the domain of f(x)=\sqrt[6]{3x-1} ?

The domain of f(x)=\sqrt[6]{3x-1} is x>= 1/3

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domain of f(x)=\sqrt[6]{3x-1}

domain

x \geq \frac{1}{3}

Interval Notation

[\frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{3}

The function domain

x \geq \frac{1}{3}

f (x) = \frac{x}{x ^{3} - 1}

f (x) = lo g_{3} (lo g_{2} (x)) = 1

h (x) = x + 2

f (x) = \frac{x - 3}{x + 4}

y = - 2

What is the domain of f(x)=\sqrt[6]{3x-1} ?
The domain of f(x)=\sqrt[6]{3x-1} is x>= 1/3